Question

part 1: go through the following electron configurations and determine which element each represents. fill in the chemical symbol in the blank to the right of the configuration. if any of the electron configurations are not valid for any element, write \invalid\ in the space.

1. (1s^{2}2s^{2}2p^{3})
2. (1s^{2})
3. (1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{6}5s^{2}4d^{10}5p^{5})
4. (1s^{2}2s^{2}2p^{4})
5. (1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{1})
6. (1s^{2}2s^{2}2p^{4}3s^{1}) invalid
7. (1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{6}5s^{2}4d^{10}5p^{6}6s^{2})
8. (1s^{2}2s^{2}2p^{6}3s^{2}3p^{6})
9. (1s^{2}2s^{2}2p^{6}3s^{2}3d^{3}) invalid
10. (1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{6}5s^{2}4d^{10}5p^{6}6s^{2}4f^{14}5d^{10}6p^{6}7s^{2}5f^{7}6d^{1})

*hint: it gets tricky with 5f and 6d, so after (7s^{2}), see that i have 8 more e-, and count down the row to 8 to find me.

1. (1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{6}5s^{2}4d^{10}5p^{6}6s^{2}4f^{14}5d^{10}6p^{6}7s^{2}5f^{4})
2. (1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{2})
3. (1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{6}5s^{2}4d^{10}5p^{6}6s^{2}4f^{14}5d^{10}6p^{6}7s^{2}6d^{1})
4. (1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}4d^{10}4p^{3})
5. (1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{6}5s^{2}4d^{10}5p^{6}6s^{2}4f^{14}5d^{5})

Explanation:

Step1: Calculate the total number of electrons

For an electron configuration \(1s^{2}2s^{2}2p^{3}\), the total number of electrons \(n = 2 + 2+3=7\).

Step2: Determine the element

The atomic number \(Z\) of an element is equal to the number of electrons in a neutral atom. The element with atomic number \(Z = 7\) is nitrogen (\(N\)).

Answer:

\(N\)