Question

part a
determine the electron geometry of ch₃oh (skeletal structure h₃coh). indicate the geometry about carbon atom.
hexahedral
trigonal planar
tetrahedral
linear
pentahedral
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part b
determine the molecular geometry of ch₃oh (skeletal structure h₃coh). indicate the geometry about carbon atom.
tetrahedral
linear
bent
trigonal pyramidal
trigonal planar

Explanation:

For Part A:
The carbon atom in \(CH_3OH\) has four regions of electron density (four single bonds: three \(C - H\) and one \(C - O\)). According to VSEPR (Valence - Shell Electron - Pair Repulsion) theory, the electron - pair geometry for an atom with four regions of electron density is tetrahedral.
For Part B:
The carbon atom in \(CH_3OH\) has four bonding pairs and no lone pairs. When an atom has four bonding pairs (and no lone pairs), according to VSEPR theory, the molecular geometry is also tetrahedral.

Answer:

Part A: tetrahedral
Part B: tetrahedral