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in parallelogram lmno, what is the measure of angle m? \\(20^\\circ\\) …

Question

in parallelogram lmno, what is the measure of angle m?

\\(20^\circ\\)
\\(60^\circ\\)
\\(80^\circ\\)
\\(100^\circ\\)

Explanation:

Response

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"Parallelogram Definition"
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"Parallelogram Definition"
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</pre_analysis>

<reasoning>

Set up the equation using consecutive interior angles

\[

$$\begin{aligned} &m\angle L + m\angle N = 180^\circ \\ &(3x + 40) + 5x = 180 \end{aligned}$$

\]

Solve for x

\[

$$\begin{aligned} &8x + 40 = 180 \\ &8x = 140 \\ &x = 17.5 \end{aligned}$$

\]

Calculate the measure of angle M

\[

$$\begin{aligned} &m\angle M = m\angle O = 180^\circ - m\angle L \\ &m\angle L = 3(17.5) + 40 = 92.5^\circ \\ &m\angle M = 180^\circ - 92.5^\circ = 87.5^\circ \quad (\text{Note: If opposite angles are equal, } m\angle M = m\angle O = 5x) \\ &m\angle M = 5x = 5(17.5) = 87.5^\circ \end{aligned}$$

\]
(Self-correction: In a standard parallelogram labeled consecutively \(L-M-N-O\), the consecutive vertices are \(L, M, N, O\). Thus, \(\angle L\) and \(\angle N\) are opposite angles, meaning \(m\angle L = m\angle N\). Let's re-evaluate:)
\[

$$\begin{aligned} &3x + 40 = 5x \\ &2x = 40 \\ &x = 20 \end{aligned}$$

\]
\[

$$\begin{aligned} &m\angle L = m\angle N = 5(20) = 100^\circ \\ &m\angle M = 180^\circ - m\angle L = 180^\circ - 100^\circ = 80^\circ \end{aligned}$$

\]
</reasoning>

<answer>
<mcq-option>(A) \(20^\circ\)</mcq-option>
<mcq-option>(B) \(60^\circ\)</mcq-option>
<mcq-correct>(C) \(80^\circ\)</mcq-correct>
<mcq-option>(D) \(100^\circ\)</mcq-option>
</answer>

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"question_type": "Multiple Choice",
"knowledge_point": [
"Mathematics",
"Geometry",
"Properties of Quadrilaterals"
]
}
</post_analysis>

Answer:

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<reasoning>

Set up the equation using consecutive interior angles

\[

$$\begin{aligned} &m\angle L + m\angle N = 180^\circ \\ &(3x + 40) + 5x = 180 \end{aligned}$$

\]

Solve for x

\[

$$\begin{aligned} &8x + 40 = 180 \\ &8x = 140 \\ &x = 17.5 \end{aligned}$$

\]

Calculate the measure of angle M

\[

$$\begin{aligned} &m\angle M = m\angle O = 180^\circ - m\angle L \\ &m\angle L = 3(17.5) + 40 = 92.5^\circ \\ &m\angle M = 180^\circ - 92.5^\circ = 87.5^\circ \quad (\text{Note: If opposite angles are equal, } m\angle M = m\angle O = 5x) \\ &m\angle M = 5x = 5(17.5) = 87.5^\circ \end{aligned}$$

\]
(Self-correction: In a standard parallelogram labeled consecutively \(L-M-N-O\), the consecutive vertices are \(L, M, N, O\). Thus, \(\angle L\) and \(\angle N\) are opposite angles, meaning \(m\angle L = m\angle N\). Let's re-evaluate:)
\[

$$\begin{aligned} &3x + 40 = 5x \\ &2x = 40 \\ &x = 20 \end{aligned}$$

\]
\[

$$\begin{aligned} &m\angle L = m\angle N = 5(20) = 100^\circ \\ &m\angle M = 180^\circ - m\angle L = 180^\circ - 100^\circ = 80^\circ \end{aligned}$$

\]
</reasoning>

<answer>
<mcq-option>(A) \(20^\circ\)</mcq-option>
<mcq-option>(B) \(60^\circ\)</mcq-option>
<mcq-correct>(C) \(80^\circ\)</mcq-correct>
<mcq-option>(D) \(100^\circ\)</mcq-option>
</answer>

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