Question

the owner of a small store buys coats for $55.00 each answer parts a and b
a he sells the coats for $66.00 each what percent of the purchase price is the sale price?
the sale price is 120 % of the purchase price

b the owner increases the sale price by the same percent that you found in part a when he buys jackets for $45 and sells them how many jackets must the owner buy to earn at least $260? explain your answer
the owner must buy 5 jacket(s)
explain your answer
he sells the jackets for 120 % of $45, or $ 260
(round to two decimal places as needed.)
260÷51 = 5 he can only sell a whole number of jackets so he needs to sell
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Explanation:

Step1: Solve part a

To find what percent of the purchase price is the sale price, we use the formula $\text{Percentage} = \frac{\text{Sale Price}}{\text{Purchase Price}} \times 100\%$. The purchase price of a coat is $\$55.00$ and the sale price is $\$66.00$. So we calculate $\frac{66}{55} \times 100\%$.
First, simplify $\frac{66}{55}=\frac{6}{5} = 1.2$. Then multiply by $100\%$: $1.2\times100\% = 120\%$.

Step2: Solve part b

First, find the sale price of each jacket. The purchase price of a jacket is $\$45$, and we use the same percentage increase as in part a (120% of the purchase price). So the sale price of one jacket is $120\%$ of $\$45$, which is $\frac{120}{100} \times 45 = 1.2\times45=\$54$.
The owner needs to earn at least $\$260$. Let $n$ be the number of jackets sold. The total revenue from selling $n$ jackets is $54n$. We need to find the smallest whole number $n$ such that $54n \geq 260$.
Solve for $n$: $n \geq \frac{260}{54} \approx 4.8148$. Since we can only sell whole jackets, we round up to the next whole number, so $n = 5$.

Answer:

a) The sale price is $120\%$ of the purchase price.
b) The owner must buy and sell 5 jackets.