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Question
in organisms, though, redox reactions involve changes in electron position in a covalent bond instead of complete loss or gain of electrons. in cellular respiration, for example, c - c bonds in glucose get broken and the electrons involved end up in c = o bonds in carbon dioxide.
which diagrams correctly represent the position of shared electrons in c - c bonds and c = o bonds? select all that apply.
when electrons in the c - c bonds of glucose end up in the c = o bonds of carbon dioxide, it means that the carbon atoms in glucose are oxidized. in the products, the electrons are farther away from the carbon atom. in other words, the carbon atom has lost access to electrons. remember - oxidation is losing
its important to realize, though, that the electrons in c - c bonds are not the only electrons in glucose that change position during cellular respiration. the electrons in glucoses c - h bonds are shared equally, but they also end up in
did you fully understand the concept covered in this section?
- For \(C - C\) bonds: Since both \(C\) atoms have the same electronegativity, the shared electrons are equally shared. In a Lewis - dot - like representation for a single \(C - C\) bond (\(C - C\)), the electrons are placed symmetrically between the two \(C\) atoms. For a double \(C = C\) bond, the same principle of equal sharing (because of identical atoms) applies.
- For \(C = O\) bonds: Oxygen is more electronegative than carbon. So, the shared electrons in the \(C = O\) bond are pulled closer to the oxygen atom.
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- For \(C - C\) bonds: The diagram with electrons equally shared between the two \(C\) atoms (e.g., if there is a diagram like \(C-\div - C\) where the dots are symmetrically placed between the \(C\) atoms) is correct.
- For \(C = O\) bonds: The diagram where the electrons in the double bond are closer to the \(O\) atom (e.g., if there is a diagram like \(C=\overset{\cdot\cdot}{:}O\) where the extra dots are on the \(O\) side of the double - bond representation) is correct.