Question

now its time to practice on your own
last week, eli took his allowance money to the store and paid $5.81 for beach toys. after that, he had no more than $2.99 left over to spend.
suppose elis dad paid eli all of his allowance with coins.
what would be the greatest number of quarters that eli could have received?
enter your answer in the box.
□ quarters

Explanation:

Step1: Find total allowance range

Let \( A \) be Eli's allowance. He spent \(\$5.81\) and had no more than \(\$2.99\) left, so \( A\leq5.81 + 2.99\). Calculate \( 5.81+2.99 = 8.8\), so \( A\leq8.8\) dollars.

Step2: Convert to cents for quarters

Since 1 dollar = 100 cents, \( 8.8\) dollars = \( 8.8\times100 = 880\) cents. A quarter is 25 cents. Let \( n \) be the number of quarters. We want to find the largest \( n \) such that \( 25n\leq880\).

Step3: Solve for n

Divide both sides by 25: \( n\leq\frac{880}{25}=35.2\). Since \( n \) must be an integer, the greatest integer \( n \) is 35.

Answer:

35