Question

nitrogen gas at 298 k and 75.5 kpa increases in pressure to 175 kpa.
what is the temperature of the gas at 175 kpa?
t = ? k

Explanation:

Step1: Use Gay-Lussac's Law

$\frac{P_1}{T_1} = \frac{P_2}{T_2}$
$T_2 = T_1 \times \frac{P_2}{P_1}$

Step2: Substitute values

$T_2 = 298\ \text{K} \times \frac{175\ \text{kPa}}{75.5\ \text{kPa}}$

Step3: Calculate result

$T_2 \approx 298 \times 2.318 \approx 691\ \text{K}$

Answer:

691 K