QUESTION IMAGE
Question
in new york state, 48% of all teenagers own a skateboard, and 39% of all teenagers own a skateboard and roller blades. we want to find the probability that a teenager owns roller blades given that the teenager owns a skateboard.
a. lets first define events a and b.
event a = teenager own a \boxed{}, event b = teenager own a \boxed{}
b. identify probabilities for each event. p(a) = \boxed{}, p(a \cap b) = \boxed{}
write your answer as a decimal.
c. using the formula below, find the probability that a teenager owns roller blades given that the teenager owns a skateboard?
\boxed{p(b|a) = \frac{p(b \cap a)}{p(a)}} p(b|a) = \boxed{}
round your answer as a decimal rounded to the nearest hundredth.
Part a: Define Events
We need to define events A and B based on the problem. The problem is about finding the probability that a teenager owns roller blades given they own a skateboard. So, Event A should be the event that a teenager owns a skateboard, and Event B should be the event that a teenager owns roller blades.
Part b: Identify Probabilities
Step 1: Find \( P(A) \)
The problem states that 48% of all teenagers own a skateboard. To convert a percentage to a decimal, we divide by 100. So, \( P(A) = \frac{48}{100} = 0.48 \).
Step 2: Find \( P(A \cap B) \)
The problem states that 39% of all teenagers own both a skateboard and roller blades. Converting this percentage to a decimal, we get \( P(A \cap B) = \frac{39}{100} = 0.39 \).
Part c: Calculate Conditional Probability
Step 1: Recall the Conditional Probability Formula
The formula for conditional probability is \( P(B|A) = \frac{P(A \cap B)}{P(A)} \).
Step 2: Substitute the Values
We know \( P(A \cap B) = 0.39 \) and \( P(A) = 0.48 \). Substituting these values into the formula, we get:
Step 3: Perform the Division
Calculating \( \frac{0.39}{0.48} \):
Step 4: Round to the Nearest Hundredth
Rounding 0.8125 to the nearest hundredth (two decimal places), we look at the third decimal place, which is 2. Since 2 < 5, we round down. So, 0.8125 rounded to the nearest hundredth is 0.81.
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s:
Part a:
Event A = teenager own a \(\boldsymbol{\text{skateboard}}\), Event B = teenager own a \(\boldsymbol{\text{roller blades}}\)
Part b:
\( P(A) = \boldsymbol{0.48} \), \( P(A \cap B) = \boldsymbol{0.39} \)
Part c:
\( P(B|A) = \boldsymbol{0.81} \) (rounded to the nearest hundredth)