Question

a negative charge of - 7.0 x 10^{-11} c and a positive charge of 1.7 x 10^{-20} c are separated by 0.0015 m. what is the force between the two charges?

Explanation:

Step1: <Coulomb's Law Formula>

Coulomb's law is \( F = k\frac{\vert q_1q_2\vert}{r^{2}}\), where \(k = 9\times10^{9}\ N\cdot m^{2}/C^{2}\), \(q_1=- 7.0\times10^{-11}\ C\), \(q_2 = 1.7\times10^{-20}\ C\), and \(r = 0.0015\ m\).

Step2: <Substitute Values>

Substitute the values into the formula:

$$
LATEXBLOCK0
$$

Step3: <Calculate Numerator>

Calculate the numerator: \((7.0\times 10^{-11})(1.7\times 10^{-20})=11.9\times 10^{-31}\)

Step4: <Calculate the Force>

$$
LATEXBLOCK1
$$

Answer:

\(4.76\times 10^{-15}\ N\)