Question

name: allen winsley jean period: 4
4.1 practice: on your own
balance the following equations. complete the charts if needed to help you.

1. na + cl₂ → __ nacl

reactants | element | products
na 2 | | na
cl 2 | |

1. h₂ + o₂ → __ h₂o

reactants | element | products
| |

1. no → n₂ + __ o₂

reactants | element | products
| |

1. mgcl₂ + k → kcl + mg

reactants | element | products
| |
try balancing the rest. if you need to make a chart, you may make your own chart below the equation.

1. albr₃ + k → kbr + al
2. feo + pdf₂ → fef₂ + pdo
3. p₄ + br₂ → __ pbr₃
4. licl + br₂ → libr + cl₂

Explanation:

Step1: Analyze Equation 1 (Na + Cl₂ → NaCl)

• Reactants: Na (1), Cl (2)
• Products: Na (1), Cl (1)
• Balance Cl: Need 2 NaCl, so NaCl coefficient = 2. Then Na on reactants needs to be 2.
• Result: 2 Na + 1 Cl₂ → 2 NaCl

Step2: Analyze Equation 2 (H₂ + O₂ → H₂O)

• Reactants: H (2), O (2)
• Products: H (2), O (1)
• Balance O: Need 2 H₂O, so H₂O coefficient = 2. Then H₂ on reactants needs to be 2.
• Result: 2 H₂ + 1 O₂ → 2 H₂O

Step3: Analyze Equation 3 (NO → N₂ + O₂)

• Reactants: N (1), O (1)
• Products: N (2), O (2)
• Balance N and O: Need 2 NO.
• Result: 2 NO → 1 N₂ + 1 O₂

Step4: Analyze Equation 4 (MgCl₂ + K → KCl + Mg)

• Reactants: Mg (1), Cl (2), K (1)
• Products: K (1), Cl (1), Mg (1)
• Balance Cl: Need 2 KCl, so KCl coefficient = 2. Then K on reactants needs to be 2.
• Result: 1 MgCl₂ + 2 K → 2 KCl + 1 Mg

Step5: Analyze 1) (AlBr₃ + K → KBr + Al)

• Reactants: Al (1), Br (3), K (1)
• Products: K (1), Br (1), Al (1)
• Balance Br: Need 3 KBr, so KBr coefficient = 3. Then K on reactants needs to be 3.
• Result: 1 AlBr₃ + 3 K → 3 KBr + 1 Al

Step6: Analyze 2) (FeO + PdF₂ → FeF₂ + PdO)

• Reactants: Fe (1), O (1), Pd (1), F (2)
• Products: Fe (1), F (2), Pd (1), O (1)
• All elements balanced with coefficient 1 for each.
• Result: 1 FeO + 1 PdF₂ → 1 FeF₂ + 1 PdO

Step7: Analyze 3) (P₄ + Br₂ → PBr₃)

• Reactants: P (4), Br (2)
• Products: P (1), Br (3)
• Balance P: Need 4 PBr₃, so PBr₃ coefficient = 4. Then Br on reactants needs to be 12, so Br₂ coefficient = 6 (since 6×2=12). P₄ coefficient = 1.
• Result: 1 P₄ + 6 Br₂ → 4 PBr₃

Step8: Analyze 4) (LiCl + Br₂ → LiBr + Cl₂)

• Reactants: Li (1), Cl (1), Br (2)
• Products: Li (1), Br (1), Cl (2)
• Balance Cl: Need 2 LiCl, so LiCl coefficient = 2. Then LiBr coefficient = 2. Br₂ and Cl₂ coefficients remain 1.
• Result: 2 LiCl + 1 Br₂ → 2 LiBr + 1 Cl₂

Answer:

1. 2 Na + 1 Cl₂ → 2 NaCl
2. 2 H₂ + 1 O₂ → 2 H₂O
3. 2 NO → 1 N₂ + 1 O₂
4. 1 MgCl₂ + 2 K → 2 KCl + 1 Mg
5. 1 AlBr₃ + 3 K → 3 KBr + 1 Al
6. 1 FeO + 1 PdF₂ → 1 FeF₂ + 1 PdO
7. 1 P₄ + 6 Br₂ → 4 PBr₃
8. 2 LiCl + 1 Br₂ → 2 LiBr + 1 Cl₂