Question

multiple choice 2 points
in the reaction $\ce{ch_{3}br + oh^{-}->ch_{3}oh + br^{-}}$, which compound acts as the nucleophile?
$\ce{ch_{3}br}$
$\ce{ch_{3}oh}$
$\ce{br^{-}}$
$\ce{oh^{-}}$
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Explanation:

A nucleophile is a species that donates an electron pair. In the reaction \(CH_3Br + OH^-\to CH_3OH + Br^-\), \(OH^-\) has a negative charge (indicating an excess of electrons) and donates an electron pair to the carbon atom in \(CH_3Br\) (which is electron - deficient due to the electronegative bromine atom). \(CH_3Br\) is the electrophile (electron - deficient species), \(CH_3OH\) is the product, and \(Br^-\) is the leaving group. So, \(OH^-\) acts as the nucleophile.

Answer:

OH⁻