Question

5.0 moles of gas take up 15.0 l of space under a set of constant pressure and temperature conditions. what volume is required to hold 2.0 moles of the gas?
v₂ = ? l

Explanation:

Step1: Apply Avogadro's Law

At constant P and T, $\frac{V_1}{n_1} = \frac{V_2}{n_2}$
Given $V_1=15.0\ \text{L}$, $n_1=5.0\ \text{mol}$, $n_2=2.0\ \text{mol}$
Rearrange: $V_2 = V_1 \times \frac{n_2}{n_1}$

Step2: Calculate $V_2$

$V_2 = 15.0\ \text{L} \times \frac{2.0\ \text{mol}}{5.0\ \text{mol}} = 6.0\ \text{L}$

Answer:

6.0 L