Question

moles of air
1.0 mole of h₂ gas fills a flexible
container. hydrogen is added until there
are 3.0 moles of h₂ or the number of
moles has tripled.
the pressure and temperature of the
system are held constant at 800 mm hg
and 300 k.
what happens to the volume of this
container?
the volume is reduced to one - third of the
original amount.
the volume is unchanged compared to the
original amount.
the volume increases to three times the original
amount.
the volume increases to six times the original
amount.

Explanation:

Step1: Apply Avogadro's Law

Avogadro's Law states $\frac{V_1}{n_1} = \frac{V_2}{n_2}$ at constant $P$ and $T$.

Step2: Calculate volume ratio

Given $n_1=1.0$ mol, $n_2=3.0$ mol: $\frac{V_2}{V_1} = \frac{n_2}{n_1} = \frac{3.0}{1.0} = 3$.

Answer:

The volume increases to three times the original amount.