Question

1. a mole is a strange unit of measurement giving the amount of a substance that contains 6.022×10²³ \elementary entities\ (atoms, molecules, etc.). the molarity is a concentration measured in moles per liter. you have a solution with a molarity of 10⁻³ moles/l and need 100 ml at 10⁻⁴ moles/l. what do you do? m₁v₁ = m₂v₂

Explanation:

Step1: Convert volume to liters

Given \(V_2 = 100\space ml=100\times10^{- 3}\space L = 0.1\space L\), \(M_1 = 10^{-3}\space mol/L\), \(M_2=10^{-4}\space mol/L\). Use the dilution formula \(M_1V_1 = M_2V_2\).

Step2: Solve for \(V_1\)

Rearrange the formula \(V_1=\frac{M_2V_2}{M_1}\). Substitute the values: \(V_1=\frac{10^{-4}\times0.1}{10^{-3}}=\frac{10^{-5}}{10^{-3}} = 0.01\space L = 10\space ml\).

Step3: Determine the operation

Take \(10\space ml\) of the \(10^{-3}\space mol/L\) solution and dilute it with water to a final volume of \(100\space ml\).

Answer:

Take \(10\space ml\) of the \(10^{-3}\space mol/L\) solution and add water to make the volume \(100\space ml\).