Question

missed this? watch kcv: writing and balancing chemical equations, iwe: balancing chemical equations. read section 4.2. you can click on the review link to access the section in your e - text. selenic acid (h2seo4) forms when solid selenium dioxide reacts with gaseous oxygen and liquid water to form aqueous selenic acid. part a enter a balanced chemical equation for this reaction. express your answer as a chemical equation. identify all of the phases in your answer. view available hint(s)

Explanation:

Step1: Write the un - balanced equation

Solid selenium ($Se$), gaseous oxygen ($O_2$) and liquid water ($H_2O$) react to form aqueous selenic acid ($H_2SeO_4$). The un - balanced equation is $Se(s)+O_2(g)+H_2O(l)
ightarrow H_2SeO_4(aq)$.

Step2: Balance the elements

First, balance the selenium atoms. There is 1 Se on both sides. Then, balance the oxygen atoms. On the left - hand side, we have 2 oxygen atoms from $O_2$ and 1 oxygen atom from $H_2O$, and on the right - hand side, we have 4 oxygen atoms in $H_2SeO_4$. Also, balance the hydrogen atoms. There are 2 hydrogen atoms on the left from $H_2O$ and 2 hydrogen atoms on the right in $H_2SeO_4$.
The balanced chemical equation is $Se(s)+2O_2(g)+H_2O(l)=H_2SeO_4(aq)$.

Answer:

$Se(s)+2O_2(g)+H_2O(l)=H_2SeO_4(aq)$