Question

the mean ages with standard deviations of four swim teams at a swim club are given below.
team | mean | standard deviation
stars | 16 | 4.1
dolphins | 18 | 1.5
giants | 14 | 0.3
mackerels | 15 | 2.3
which statement is most likely to be true?

• the ages of the mackerels are the most dispersed from the team’s mean.
• the ages of the stars are the most dispersed from the team’s mean.
• the ages of the dolphins are the most dispersed from the team’s mean.
• the ages of the giants are the most dispersed from the team’s mean.

Explanation:

Step1: Recall SD meaning

Standard Deviation (SD) measures data dispersion from the mean. Larger SD means more dispersion.

Step2: Compare SD values

Teams' SD: Stars ($4.1$), Dolphins ($1.5$), Giants ($0.3$), Mackerels ($2.3$).

Step3: Identify largest SD

$4.1$ (Stars) is the largest among $4.1, 1.5, 0.3, 2.3$.

Answer:

The ages of the Stars are the most dispersed from the team’s mean. (Corresponding option: "The ages of the Stars are the most dispersed from the team’s mean.")