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Question
- add \\(\frac{9}{16} + \frac{5}{12}\\). \\(\frac{47}{48}\\) \\(\frac{35}{36}\\) \\(\frac{1}{2}\\) \\(\frac{17}{18}\\)
Step1: Find the least common denominator (LCD) of 16 and 12.
The prime factorization of 16 is \(2^4\) and of 12 is \(2^2\times3\). So, LCD is \(2^4\times3 = 48\).
Step2: Rewrite the fractions with the LCD.
For \(\frac{9}{16}\), multiply numerator and denominator by 3: \(\frac{9\times3}{16\times3}=\frac{27}{48}\).
For \(\frac{5}{12}\), multiply numerator and denominator by 4: \(\frac{5\times4}{12\times4}=\frac{20}{48}\).
Step3: Add the fractions.
\(\frac{27}{48}+\frac{20}{48}=\frac{27 + 20}{48}=\frac{47}{48}\).
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\(\frac{47}{48}\) (corresponding to the first option among the choices, likely labeled with \(\frac{47}{48}\))