QUESTION IMAGE
Question
match the trig ratios
= \frac{\text{opposite}}{\text{hypotenuse}}
= \frac{\text{adjacent}}{\text{hypotenuse}}
= \frac{\text{opposite}}{\text{adjacent}}
⚡ Using what you learned: right triangle trigonometry (soh cah toa)
Step 1: Identify the sine ratio
$$
\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}
$$
Step 2: Identify the cosine ratio
$$
\cos(\theta) = \frac{\text{adjacent}}{\text{hypotenuse}}
$$
Step 3: Identify the tangent ratio
$$
\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}}
$$
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- sine (or sin) \( = \frac{\text{opposite}}{\text{hypotenuse}} \)
- cosine (or cos) \( = \frac{\text{adjacent}}{\text{hypotenuse}} \)
- tangent (or tan) \( = \frac{\text{opposite}}{\text{adjacent}} \)