Question

match each correct answer to a letter and complete the riddle below.
1 a toy manufacturer estimates that 6% of its products are defective. if 550 toys are produced in one day, how many will be defective?
2 fourteen percent of the towns population is over the age of 65. if there are 320 residents over the age of 65, approximately what is the towns population?
3 the la dodgers hit the most homeruns in 2014. the number of homeruns accounted for 6% of the entire major league baseball homerun count. if 583 total homeruns were hit, approximately how many did the la dodgers hit?
4 two of the dozen eggs in a carton are cracked. about what percent of the carton is cracked?
5 mr. hollins determines that he gives away $800 each month. if he gives away 16% of his budget, how much is his overall budget?
6 eddie is reading a novel for english class. he has read 173 out of 480 pages. about what percent of the book has he read?
7 a nutrition label states that there are 36g of carbohydrates in each serving. this accounts for 12% of the daily value. how many grams of carbohydrates are recommended per day?
8 about 56% of the 2,553 students are enrolled in at least one honors class. how many students are enrolled in an honors class?
t: 33
o: 25
c: 36
j: 4
m: 517
k: 64
q: 65
l: 2,286
a: 35
p: 4,559
h: 128
g: 16.7
i: 800
e: 300
r: 5,000
v: 45
n: 1,430
s: 80
d: 1,129
b: 18.7
what do you call a destroyed angle?
_ _ _ _ _ _ _ _ _ _
3 5 7 6 1 3 8 4 2 7

Explanation:

Step1: Solve problem 1

The formula for calculating the number of defective toys is \( \text{Number of defective toys}=\text{Percentage of defective toys}\times\text{Total number of toys produced}\). Given that the percentage of defective toys is \(6\% = 0.06\) and the total number of toys produced is \(550\). So, \(0.06\times550 = 33\).

Step2: Solve problem 2

We use the formula \( \text{Percentage}=\frac{\text{Part}}{\text{Whole}}\times100\%\), which can be rewritten as \( \text{Whole}=\frac{\text{Part}}{\text{Percentage}}\). Here, the part is \(320\) (residents over 65) and the percentage is \(14\%=0.14\). So, \( \frac{320}{0.14}\approx2286\).

Step3: Solve problem 3

Using the formula \( \text{Part}=\text{Percentage}\times\text{Whole}\). The percentage is \(6\% = 0.06\) and the whole is \(583\). So, \(0.06\times583\approx 35\).

Step4: Solve problem 4

A dozen eggs means \(n = 12\) eggs. The formula for percentage is \( \text{Percentage}=\frac{\text{Number of cracked eggs}}{\text{Total number of eggs}}\times100\%\). Number of cracked eggs is \(2\), total number of eggs is \(12\). So, \( \frac{2}{12}\times100\%\approx16.7\%\).

Step5: Solve problem 5

Using the formula \( \text{Percentage}=\frac{\text{Part}}{\text{Whole}}\times100\%\), rewritten as \( \text{Whole}=\frac{\text{Part}}{\text{Percentage}}\). The part is \(800\), the percentage is \(16\% = 0.16\). So, \( \frac{800}{0.16}=5000\).

Step6: Solve problem 6

Using the formula \( \text{Percentage}=\frac{\text{Number of pages read}}{\text{Total number of pages}}\times100\%\). Number of pages read is \(173\), total number of pages is \(480\). So, \( \frac{173}{480}\times100\%\approx36\%\).

Step7: Solve problem 7

Using the formula \( \text{Percentage}=\frac{\text{Part}}{\text{Whole}}\times100\%\), rewritten as \( \text{Whole}=\frac{\text{Part}}{\text{Percentage}}\). The part is \(36\)g, the percentage is \(12\%=0.12\). So, \( \frac{36}{0.12}=300\)g.

Step8: Solve problem 8

Using the formula \( \text{Part}=\text{Percentage}\times\text{Whole}\). The percentage is \(56\% = 0.56\), the whole is \(2553\). So, \(0.56\times2553 = 1430\).

Answer:

For problem 1: \(33\) (T), problem 2: \(2286\) (L), problem 3: \(35\) (A), problem 4: \(16.7\) (G), problem 5: \(5000\) (R), problem 6: \(36\) (C), problem 7: \(300\) (E), problem 8: \(1430\) (N).
The letters corresponding to the answers (in order of problem numbers \(3,5,7,6,1,3,8,4,2,7\)) are \(T, R, E, C, T, E, N, G, L, E\).