Question

martin puts two bowls of fruit out for his friends. the bowl of grapes has 9 green grapes and 16 red grapes. the bowl of tangerines has 7 seeded and 3 seedless tangerines. martins friend chooses a random grape and a random tangerine. what is the probability that she chooses a green grape and a seedless tangerine? enter the answer in the box. \frac{\quad}{\quad}

Explanation:

Step1: Calculate total grapes

Total grapes = green + red = \( 9 + 16 = 25 \)

Step2: Probability of green grape

Probability (green grape) = \( \frac{9}{25} \)

Step3: Calculate total tangerines

Total tangerines = seeded + seedless = \( 7 + 3 = 10 \)

Step4: Probability of seedless tangerine

Probability (seedless tangerine) = \( \frac{3}{10} \)

Step5: Multiply probabilities (independent events)

Combined probability = \( \frac{9}{25} \times \frac{3}{10} = \frac{27}{250} \)

Answer:

\(\frac{27}{250}\)