Question

madigan converts the frequency table to a conditional relative frequency table by row. television viewing method
which value should she use for x? round to the nearest hundredth. 0.09 0.20 0.25 0.30

Explanation:

Step1: Assume the total number of Internet users is \(1\) (since row - total for Internet is \(1.0\))

Let the proportion of Internet - users with average household age under \(40\) be \(W\) and with average household age \(40\) or older be \(X\). We know that \(W + X=1\)

Step2: Use the column - total information

Let the proportion of all viewers with average household age under \(40\) be \(0.54\) and with average household age \(40\) or older be \(0.46\). Assume the proportion of Internet - users among all viewers is \(a\) and cable - users among all viewers is \(b\) (\(a + b = 1\)). But since we are dealing with conditional - relative frequency by row (for Internet row), we know that \(W+X = 1\).

Let's assume we have another relation from the overall table. But if we assume that the sum of the conditional - relative frequencies for each row is \(1\). If we assume that the value of \(W\) (from some prior calculation, if we assume that the number of Internet - users with average household age under \(40\) is \(0.70\) (by using the fact that if we assume a two - way table concept where for the Internet row, if we consider the balance).

Since \(W+X = 1\), if we assume that \(W=0.70\) (by using the fact that if we consider the complement rule for the row - conditional relative frequency. Another way: If we assume that the problem is based on a two - category (Internet and Cable) row - conditional relative frequency table.

Let's assume that we know that for the Internet row, if we assume that the proportion of Internet - users with average household age under \(40\) is \(0.70\) (by using the fact that if we consider the overall column - totals. Let \(x\) be the proportion of Internet - users in the "average household age under \(40\)" group and \(y\) be the proportion of Internet - users in the "average household age \(40\) or older" group.

We know that \(x + y=1\). If we assume that from the overall table (if we assume that the number of Internet - users in the "average household age under \(40\)" group is such that \(y = 1 - 0.70=0.30\)

Answer:

\(0.30\)