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linear equations w/ distribution (lev 1) score: 3/5 penalty: none quest…

Question

linear equations w/ distribution (lev 1)
score: 3/5 penalty: none
question
solve.
$3(z + 2) = 9$

Explanation:

Step1: Expand the left - hand side

Use the distributive property \(a(b + c)=ab+ac\). Here \(a = 3\), \(b=z\), \(c = 2\). So \(3(z + 2)=3z+6\). The equation becomes \(3z+6 = 9\).

Step2: Isolate the term with the variable

Subtract 6 from both sides of the equation. \(3z+6-6=9 - 6\). This simplifies to \(3z=3\).

Step3: Solve for \(z\)

Divide both sides of the equation by 3. \(\frac{3z}{3}=\frac{3}{3}\).

Answer:

\(z = 1\)