Question

laura tosses two dice. find the probability of getting a 3 on each die.
options:
\\(\frac{1}{6}\\)
\\(\frac{1}{9}\\)
\\(\frac{1}{12}\\)
\\(\frac{1}{36}\\)

Explanation:

Step1: Probability of 3 on one die

A die has 6 faces. Probability of getting 3 on one die is $P(3)=\frac{1}{6}$.

Step2: Probability for two dice (independent events)

For two independent events, the probability of both occurring is the product of their individual probabilities. So for two dice, $P(\text{3 on both}) = P(3) \times P(3)=\frac{1}{6} \times \frac{1}{6}=\frac{1}{36}$.

Answer:

$\frac{1}{36}$ (corresponding to the option with $\frac{1}{36}$)