QUESTION IMAGE
Question
- kyle is doing a chemistry experiment and has 30 ml of a 25% solution. how many ml of a 80% solution should he add to obtain a mixture that is a 50% solution?
| amount | % | total | |
|---|---|---|---|
| solution 2 | x | 80 | 80x |
| mixture | x + 30 | 50 | 5(x + 30) |
Step1: Set up equation based on mixture principle
The amount of pure substance before mixing equals the amount of pure substance after mixing. For the first - solution, the amount of pure substance is \(30\times0.25 = 7.5\). For the second - solution, the amount of pure substance is \(0.8x\). And for the mixture, the amount of pure substance is \(0.5(x + 30)\). So the equation is \(30\times0.25+0.8x=0.5(x + 30)\).
Step2: Expand and simplify the equation
$$
LATEXBLOCK0
$$
Step3: Solve for \(x\)
$$
LATEXBLOCK1
$$
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