Question

julio has two bags of gummy candies. one at a time, he randomly pulled 8 pineapple, 5 lime, and 7 strawberry candies out of the first bag and put them back each time. he also randomly pulled 11 mango, 3 tamarind, and 6 watermelon candies out of the second bag and put them back each time.
based on this information, what is the probability that julio will select a strawberry candy from the first bag and a tamarind candy from the second bag the next time he takes a candy from each bag?
type a number in each box.

Explanation:

Step1: Find total in first bag

First bag: 8 (pineapple) + 5 (lime) + 7 (strawberry) = 20 total.

Step2: Probability of strawberry (first bag)

Probability (strawberry) = $\frac{7}{20}$.

Step3: Find total in second bag

Second bag: 11 (mango) + 3 (tamarind) + 6 (watermelon) = 20 total.

Step4: Probability of tamarind (second bag)

Probability (tamarind) = $\frac{3}{20}$.

Step5: Multiply probabilities (independent events)

Combined probability = $\frac{7}{20} \times \frac{3}{20} = \frac{21}{400}$.

Answer:

$\frac{21}{400}$