Question

a jar has 8 jellybeans: 5 red, 3 green. if 1 jellybean is randomly drawn, replaced, and then 1 is drawn again, what is the probability of getting red, then green? event a: red on 1st draw event b: green on 2nd draw p(a, then b) = ? / ? give your answer as a fraction in simplest form compound probability independent events p(a, then b) = p(a) · p(b)

Explanation:

Step1: Calculate P(A)

P(A) = number of red jellybeans / total jellybeans = $\frac{5}{8}$

Step2: Calculate P(B)

P(B) = number of green jellybeans / total jellybeans = $\frac{3}{8}$

Step3: Find P(A then B)

Multiply P(A) and P(B): $\frac{5}{8} \times \frac{3}{8} = \frac{15}{64}$

Answer:

$\frac{15}{64}$