Question

an item is randomly drawn from a bag with 16 fruit cups, 3 vegetable cups, 14 fruit cans, and 7 vegetable cans. event a: fruit event b: can p(a or b) = ? hint: p(a or b) = p(a) + p(b) - p(a and b) round your answer to the nearest hundredth.

Explanation:

Step1: Calculate total items

Total = 16 + 3 + 14 + 7 = 40

Step2: Find P(A)

Fruit items = 16 + 14 = 30; $P(A) = \frac{30}{40} = 0.75$

Step3: Find P(B)

Can items = 14 + 7 = 21; $P(B) = \frac{21}{40} = 0.525$

Step4: Find P(A and B)

Fruit cans = 14; $P(A \cap B) = \frac{14}{40} = 0.35$

Step5: Compute P(A or B)

$P(A \cup B) = 0.75 + 0.525 - 0.35 = 0.925 ≈ 0.93$

Answer:

0.93