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an item is randomly drawn from a bag with 16 fruit cups, 3 vegetable cu…

Question

an item is randomly drawn from a bag with 16 fruit cups, 3 vegetable cups, 14 fruit cans, and 7 vegetable cans. event a: vegetable event b: cup p(a or b) = ? hint: p(a or b) = p(a) + p(b) - p(a and b) round your answer to the nearest hundredth.

Explanation:

Step1: Calculate total items

Total = 16 + 3 + 14 + 7 = 40

Step2: Find P(A)

Number of vegetable items = 3 + 7 = 10, so $P(A)=\frac{10}{40}=0.25$

Step3: Find P(B)

Number of cup items = 16 + 3 = 19, so $P(B)=\frac{19}{40}=0.475$

Step4: Find P(A and B)

Number of vegetable cups = 3, so $P(A\cap B)=\frac{3}{40}=0.075$

Step5: Compute P(A or B)

$P(A\cup B)=0.25 + 0.475 - 0.075 = 0.65$

Answer:

0.65