Question

isotope name (symbol) protons neutrons electrons mass number atomic number isotopic symbol (az notation)
62 99
40 ²²ₙ
nickel - 58 28
part ii: the next 5 questions are regarding the isotope below: ⁵⁷₂₆fe

1. what is the name (just the name) of this isotope?
2. what is the atomic number of this isotope?
3. how many protons are in this isotope?
4. what is the mass number of this isotope?
5. how many neutrons are in this isotope?

part iii: solve for atomic mass. equation is given to you in the box below. show your work below. write your final answer on the line. round to one decimal and include your units!
avg. atomic mass=(isotope mass₁ x abundance₁)+(isotope mass₂ x abundance₂)
an element has the following natural abundances and isotope masses: 51.8% abundance with mass of 106.91 amu and 48.2% abundance with a mass of 108.91 amu. calculate the average atomic mass of this element.
show work here:

Explanation:

Part II

Step1: Name of isotope

The symbol $\ce{^{57}_{26}Fe}$ represents iron - 57.

Step2: Atomic number

The sub - script in the isotope notation $\ce{^{A}_{Z}X}$ is the atomic number. For $\ce{^{57}_{26}Fe}$, the atomic number $Z = 26$.

Step3: Number of protons

The number of protons is equal to the atomic number. So, there are 26 protons.

Step4: Mass number

The mass number is the superscript in the isotope notation. For $\ce{^{57}_{26}Fe}$, the mass number $A=57$.

Step5: Number of neutrons

The number of neutrons $N=A - Z$. So, $N = 57-26=31$.

Part III

Step1: Identify values

Let $m_1 = 106.91$ amu, $a_1=0.518$, $m_2 = 108.91$ amu, $a_2 = 0.482$.

Step2: Apply formula

The formula for average atomic mass is $\text{Average atomic mass}=(m_1\times a_1)+(m_2\times a_2)$.

$$
LATEXBLOCK0
$$

Rounding to one decimal place, the average atomic mass is $108.1$ amu.

Answer:

Part II

1. Iron - 57
2. 26
3. 26
4. 57
5. 31

Part III

108.1 amu