Question

ionic compound formulas
compound made from sodium and iodine.
is in group 1.
group 7a or 17.
what is the formula for the ionic compound of sodium (na)
and iodine (i)?
nal
nal
nal
nal

Explanation:

Step1: Determine the charges of ions

Sodium (Na) is in group 1, so it loses 1 electron and forms \(Na^{+}\) (charge \(+ 1\)). Iodine (I) is in group 17 (7A), so it gains 1 electron and forms \(I^{-}\) (charge \(-1\)).

Step2: Write the formula of ionic compound

In an ionic compound, the sum of charges of cations and anions is zero. Since the charge of \(Na^{+}\) is \(+1\) and the charge of \(I^{-}\) is \(-1\), the ratio of \(Na^{+}\) to \(I^{-}\) is \(1:1\). The formula of the ionic compound is \(NaI\).

Answer:

\(NaI\) (the second option in the multiple - choice list)