Question

interpreting the question
the given is
the balanced equation is
br₂ + 2nai → i₂ + 2nabr
how many moles of i₂ form when 5.0 mol nai react with
what is the ratio needed from the balanced equation?
2 mol nai: 1 mol i₂
3 mol nai: 1 mol i₂
4 mol nai: 1 mol i₂
5.0 mol nai / x mol i₂ = ?/?

Explanation:

Step1: Analyze the balanced equation

From the balanced equation \(Br_{2}+2NaI
ightarrow I_{2}+2NaBr\), we can see that the mole ratio of \(NaI\) to \(I_{2}\) is \(2:1\).

Step2: Set up the proportion

We have \(\frac{5.0\space mol\space NaI}{x\space mol\space I_{2}}=\frac{2\space mol\space NaI}{1\space mol\space I_{2}}\)

Answer:

\(\frac{5.0\space mol\space NaI}{x\space mol\space I_{2}}=\frac{2\space mol\space NaI}{1\space mol\space I_{2}}\)