Question

identify the strong acid in the following reaction, and then predict the products: hclo4(aq) + naoh(aq) →?
o there is no strong acid present and the results are impossible to predict.
o naoh; h2o(l) + hclo4(aq)
o naoh; h2o(l) + naclo4(aq)
o hclo4; h2o(l) + naclo4(aq)

Explanation:

Step1: Recall acid - base reaction rules

When a strong acid reacts with a strong base, they undergo a neutralization reaction. \(HClO_4\) is a strong acid (completely dissociates in water) and \(NaOH\) is a strong base (completely dissociates in water). The general form of the reaction between an acid \(HA\) and a base \(MOH\) is \(HA+MOH
ightarrow H_2O + MA\).

Step2: Write the reaction equation

For \(HClO_4(aq)+NaOH(aq)\), substituting into the general form:
\(HClO_4(aq)+NaOH(aq)
ightarrow H_2O(l)+NaClO_4(aq)\)

Answer:

\(HClO_4;H_2O(l)+NaClO_4(aq)\)