Question

identify the glucose anomer based on the hydroxyl position from the following structure.
select the correct answer below:
β-glucose

Explanation:

In the Haworth projection of glucose, if the hydroxyl group ($\ce{-OH}$) at the anomeric carbon (carbon - 1) is on the same side as the $\ce{-CH_{2}OH}$ group (carbon - 5), it is β - glucose. In the given structure, the $\ce{-OH}$ at carbon - 1 and $\ce{-CH_{2}OH}$ at carbon - 5 are on the same side (both above the plane of the ring), so it is β - glucose.

Answer:

β-glucose