4. identify the appropriate block on the periodic table for each description by placing an x in the correct column.
| | s block | p block | d block | f block |
| --- | --- | --- | --- | --- |
| $1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^8$ | | | | |
| $xe 4f^{14} 5d^{10} 6s^2 6p^1$ | | | | |
| uranium | | | | |
| calcium | | | | |
| cobalt | | | | |
| selenium | | | | |
| $1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^{10} 5p^6 6s^2$ | | | | |

Question

4. identify the appropriate block on the periodic table for each description by placing an x in the correct column.
| | s block | p block | d block | f block |
| --- | --- | --- | --- | --- |
| $1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^8$ |  |  |  |  |
| $xe 4f^{14} 5d^{10} 6s^2 6p^1$ |  |  |  |  |
| uranium |  |  |  |  |
| calcium |  |  |  |  |
| cobalt |  |  |  |  |
| selenium |  |  |  |  |
| $1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^{10} 5p^6 6s^2$ |  |  |  |  |

Accepted Answer

# Explanation:
## Step 1: Recall Block Definitions
- **s - block**: Elements with valence electrons in $ s $ orbitals (groups 1, 2, He). Electron configuration ends with $ ns^1 $ or $ ns^2 $.
- **p - block**: Elements with valence electrons in $ p $ orbitals (groups 13 - 18). Electron configuration ends with $ np^1 - np^6 $.
- **d - block**: Transition metals, electron configuration involves $ (n - 1)d $ orbitals (groups 3 - 12).
- **f - block**: Lanthanides and actinides, electron configuration involves $ (n - 2)f $ orbitals.

## Step 2: Analyze Each Entry
1. **$ 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 $**:
   Valence electron: $ 4s^2 $ (s - block, group 2). So s - block.
2. **$ [Xe] 4f^{14} 5d^{10} 6s^2 6p^2 $**:
   Valence electrons: $ 6s^2 6p^2 $ (p - block, group 14). So p - block.
3. **Uranium (U)**:
   Uranium is an actinide (f - block), electron configuration involves $ 5f $ orbitals. So f - block.
4. **Calcium (Ca)**:
   Electron configuration: $ [Ar] 4s^2 $ (s - block, group 2). So s - block.
5. **Cobalt (Co)**:
   Transition metal, electron configuration: $ [Ar] 3d^7 4s^2 $ (d - block). So d - block.
6. **Selenium (Se)**:
   Electron configuration: $ [Ar] 3d^{10} 4s^2 4p^4 $ (p - block, group 16). So p - block.
7. **$ 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^{10} 5p^6 6s^2 $**:
   Valence electron: $ 6s^2 $ (s - block, group 2, element Fr? Wait, no—wait, this is a noble gas? Wait, no, $ 6s^2 $ with filled inner shells. Wait, actually, this is Radium? Wait, no, the electron configuration here: $ 6s^2 $ (s - block, group 2). So s - block.

# Answer:
| Description                          | s - block | p - block | d - block | f - block |
|--------------------------------------|-----------|-----------|-----------|-----------|
| $ 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 $  | X         |           |           |           |
| $ [Xe] 4f^{14} 5d^{10} 6s^2 6p^2 $  |           | X         |           |           |
| Uranium                              |           |           |           | X         |
| Calcium                              | X         |           |           |           |
| Cobalt                               |           |           | X         |           |
| Selenium                             |           | X         |           |           |
| $ 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^{10} 5p^6 6s^2 $ | X | | | |

Sovi.AI - AI Math Tutor

QUESTION IMAGE

Question

Explanation:

Step 1: Recall Block Definitions

Step 2: Analyze Each Entry

Answer:

	s block	p block	d block	f block
$xe 4f^{14} 5d^{10} 6s^2 6p^1$
uranium
calcium
cobalt
selenium
$1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^{10} 5p^6 6s^2$

Description	s - block	p - block	d - block	f - block
\( [Xe] 4f^{14} 5d^{10} 6s^2 6p^2 \)		X
Uranium				X
Calcium	X
Cobalt			X
Selenium		X
\( 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^{10} 5p^6 6s^2 \)	X