Question

how much heat would need to be absorbed by 1.5 g of liquid water to raise its temperature by 30.45 °c?
the specific heat of liquid water is 4.18 j/g°c.
round your answer to the nearest whole number.
a 191 j
b 127 j
c 11 j
d 150 j

Explanation:

Step1: Recall the heat - absorption formula

The formula for heat absorbed \(Q = mc\Delta T\), where \(m\) is the mass, \(c\) is the specific heat capacity, and \(\Delta T\) is the change in temperature.

Step2: Substitute the given values into the formula

Given \(m = 1.5\space g\), \(c=4.18\space J/g^{\circ}C\), and \(\Delta T = 30.45^{\circ}C\).

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Step3: Round the result

Rounding \(190.9215\) to the nearest whole number gives \(191\).

Answer:

A. \(191\space J\)