Question

how much energy does the water in this experiment absorb according to the calorimeter data?

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$$\begin{tabular}{|l|c|} \\hline \\multicolumn{2}{|c|}{calorimeter data} \\\\ \\hline mass (g) & 50.0 \\\\ \\hline specific heat (\\text{j}/\\text{g}^{\\circ}\\text{c}) & 4.18 \\\\ \\hline \\text{t}_i (^{\\circ}\\text{c}) & 20.5 \\\\ \\hline \\text{t}_f (^{\\circ}\\text{c}) & 32.5 \\\\ \\hline \\end{tabular}$$

\\(q_{\text{h}_2\text{o}} = ? \text{ j}\\)

Explanation:

Identify given values

We extract parameters:

• Mass \(m = 50.0\text{ g}\)
• Specific heat \(c = 4.18\text{ J/(g}\cdot^\circ\text{C)}\)
• Initial temperature \(T_i = 20.5^\circ\text{C}\)
• Final temperature \(T_f = 32.5^\circ\text{C}\)

Calculate temperature change

Find temperature difference:

$$ \Delta T = T_f - T_i = 32.5^\circ\text{C} - 20.5^\circ\text{C} = 12.0^\circ\text{C} $$

Calculate heat absorbed

Apply heat formula:

$$ q = m \cdot c \cdot \Delta T $$

$$ q = 50.0\text{ g} \cdot 4.18\text{ J/(g}\cdot^\circ\text{C)} \cdot 12.0^\circ\text{C} $$

$$ q = 2508\text{ J} $$

Answer:

How much energy does the water in this experiment absorb according to the calorimeter data?

\(q_{\text{H}_2\text{O}} =\) <blank>\(2508\)</blank> J