Question

how much energy does the water in this experiment absorb according to the calorimeter data?

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$$\begin{tabular}{|l|c|} \\hline \\multicolumn{2}{|c|}{calorimeter data} \\\\ \\hline mass (g) & 200.0 \\\\ \\hline specific heat (\\text{j}/\\text{g}^{\\circ}\\text{c}) & 4.18 \\\\ \\hline t_i (^{\\circ}\\text{c}) & 20.1 \\\\ \\hline t_f (^{\\circ}\\text{c}) & 45.1 \\\\ \\hline \\end{tabular}$$

q_{\text{h}_2\text{o}} = ? \text{ j}

Explanation:

Identify the given values

We extract the following values from the calorimeter data table:

• Mass of water \(m = 200.0\text{ g}\)
• Specific heat capacity of water \(c = 4.18\text{ J/g}^\circ\text{C}\)
• Initial temperature \(T_i = 20.1^\circ\text{C}\)
• Final temperature \(T_f = 45.1^\circ\text{C}\)

Calculate the temperature change

Using the Specific Heat Capacity concept:

$$ \Delta T = T_f - T_i $$

$$ \Delta T = 45.1^\circ\text{C} - 20.1^\circ\text{C} = 25.0^\circ\text{C} $$

Calculate the absorbed energy

Using the Calorimetry Calculations concept:

$$ q_{\text{H}_2\text{O}} = m \cdot c \cdot \Delta T $$

$$ q_{\text{H}_2\text{O}} = 200.0\text{ g} \times 4.18\text{ J/g}^\circ\text{C} \times 25.0^\circ\text{C} $$

$$ q_{\text{H}_2\text{O}} = 20900\text{ J} $$

Answer:

How much energy does the water in this experiment absorb according to the calorimeter data?

\(q_{\text{H}_2\text{O}} =\) <blank>20900</blank> J