Question

how many total atoms of each element are present in the following formulas? 4 cacl₂ + 2 ca(clo₄)₂ + 5 ca(oh)₂ tap in the fields to enter the answers directly or tap on the number pad icon to use our built - in number pad. calcium (ca) chlorine (cl) oxygen (o) hydrogen (h)

Explanation:

Step1: Calculate the number of Ca atoms

For \(4CaCl_2\), the number of Ca atoms is \(4\times1 = 4\). For \(2Ca(ClO_4)_2\), the number of Ca atoms is \(2\times1=2\). For \(5Ca(OH)_2\), the number of Ca atoms is \(5\times1 = 5\).

$$4 + 2+5=11$$

Step2: Calculate the number of Cl atoms

For \(4CaCl_2\), the number of Cl atoms is \(4\times2 = 8\). For \(2Ca(ClO_4)_2\), the number of Cl atoms is \(2\times2=4\).

$$8 + 4=12$$

Step3: Calculate the number of O atoms

For \(2Ca(ClO_4)_2\), the number of O atoms is \(2\times(4\times2)=16\). For \(5Ca(OH)_2\), the number of O atoms is \(5\times2 = 10\).

$$16+10=26$$

Step4: Calculate the number of H atoms

For \(5Ca(OH)_2\), the number of H atoms is \(5\times2=10\).

Answer:

Calcium (\(Ca\)): \(11\)
Chlorine (\(Cl\)): \(12\)
Oxygen (\(O\)): \(26\)
Hydrogen (\(H\)): \(10\)