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Question
how many oxygen atoms are in the formula fe₂(cr₂o₇)₃? view available hint(s) 3 6 7 21
Step1: Analyze the sub - formula for oxygen
In the formula \(Fe_2(Cr_2O_7)_3\), the part related to oxygen is \(O_7\) within the parentheses.
Step2: Consider the multiplier outside the parentheses
The multiplier outside the parentheses \((Cr_2O_7)\) is 3. To find the total number of oxygen atoms, we multiply the number of oxygen atoms in the sub - formula (\(O_7\)) by the multiplier. So we calculate \(7\times3\).
$$7\times3 = 21$$
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