Question

how many moles are present in 3.01 x 10^{23} atoms c?
3.01 x 10^{23} atoms c
remember: 1 mole = 6.02 x 10^{23} particles
1.00 mole c
0.500 moles c
2.00 moles c
5.00 x 10^{45} moles c

Explanation:

Step1: Apply the conversion formula

The formula to convert number of atoms to moles is \(n=\frac{N}{N_A}\), where \(n\) is the number of moles, \(N\) is the number of atoms, and \(N_A = 6.02\times10^{23}\text{ particles/mole}\) (Avogadro's number). Given \(N = 3.01\times 10^{23}\text{ atoms C}\).

$$n=\frac{3.01\times 10^{23}\text{ atoms C}}{6.02\times 10^{23}\text{ atoms/mole}}$$

Step2: Simplify the expression

Divide \(3.01\times 10^{23}\) by \(6.02\times 10^{23}\). The \(10^{23}\) terms cancel out (\(\frac{10^{23}}{10^{23}} = 1\)), and \(\frac{3.01}{6.02}=0.5\).

Answer:

\(0.500\) moles C