Question

how many moles of nacl are contained in each volume of aqueous nacl solution? be sure each of your answer entries has the correct number of significant figures. note: reference the si prefixes table for additional information. part 1 of 2 4.9 l of a 0.43 m solution mol nacl part 2 of 2 320. ml of a 0.53 m solution mol nacl

Explanation:

Step1: Recall the formula for moles

The formula for moles \(n\) in a solution is \(n = C\times V\), where \(C\) is the molarity and \(V\) is the volume in liters.

Step2: Calculate for Part 1

Given \(C = 0.43\space M\) and \(V=4.9\space L\).
Substitute into the formula: \(n = 0.43\times4.9\).

$$n=0.43\times4.9 = 2.107$$

Rounding to two significant figures (since \(0.43\) has two and \(4.9\) has two), \(n = 2.1\space mol\).

Step3: Convert volume for Part 2

Given \(V = 320\space mL\). Convert to liters: \(V=\frac{320}{1000}=0.320\space L\) (three significant figures). \(C = 0.53\space M\) (two significant figures).

Step4: Calculate for Part 2

Substitute into \(n = C\times V\): \(n=0.53\times0.320\).

$$n = 0.53\times0.320=0.1696$$

Rounding to two significant figures (based on \(0.53\)), \(n = 0.17\space mol\).

Answer:

Part 1: \(2.1\space mol\)
Part 2: \(0.17\space mol\)