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Question
how many moles of chlorine gas are needed to make 0.6 moles of sodium chloride? given the reaction 2na + cl₂ → 2nacl. options: 0.3, 0.6, 1.2, 3.6, not enough information.
Step1: Analyze the reaction stoichiometry
The balanced chemical reaction is \( 2\text{Na} + \text{Cl}_2
ightarrow 2\text{NaCl} \). From this reaction, we can see that the mole ratio of \( \text{Cl}_2 \) to \( \text{NaCl} \) is \( 1:2 \) (1 mole of \( \text{Cl}_2 \) produces 2 moles of \( \text{NaCl} \)).
Step2: Set up the proportion to find moles of \( \text{Cl}_2 \)
Let \( x \) be the moles of \( \text{Cl}_2 \) needed. We know that \( \frac{\text{moles of } \text{Cl}_2}{\text{moles of } \text{NaCl}} = \frac{1}{2} \). We are given that moles of \( \text{NaCl} = 0.6 \) moles. So, \( \frac{x}{0.6} = \frac{1}{2} \).
Step3: Solve for \( x \)
Cross - multiply the proportion: \( 2x = 0.6\times1 \). Then, \( x=\frac{0.6}{2}=0.3 \) moles.
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0.3 (corresponding to the option "0 3" in the given choices)