Question

how many moles of ammonium nitrate would be required to have 3.55 moles of oxygen? 1.18 mol o 3.55 mol o 1.78 mol o 10.7 mol o

Explanation:

Step1: Determine the chemical formula of ammonium nitrate

The chemical formula of ammonium nitrate is \(NH_4NO_3\).

Step2: Analyze the number of oxygen atoms in ammonium nitrate

In \(NH_4NO_3\), there are 3 oxygen atoms per formula unit.

Step3: Set up the mole - ratio relationship

Let \(n\) be the number of moles of \(NH_4NO_3\). The mole - ratio of \(O\) to \(NH_4NO_3\) is \(3:1\).
We know that the number of moles of \(O\) is \(n_O = 3.55\space mol\). Using the ratio \(\frac{n_O}{n_{NH_4NO_3}}=\frac{3}{1}\), we can solve for \(n_{NH_4NO_3}\).

$$n_{NH_4NO_3}=\frac{n_O}{3}$$

Step4: Calculate the number of moles of ammonium nitrate

Substitute \(n_O = 3.55\space mol\) into the formula:

$$n_{NH_4NO_3}=\frac{3.55\space mol}{3}\approx1.18\space mol$$

Answer:

1.18 mol \(NH_4NO_3\) (corresponds to the first option \(1.18\space mol\space O\) if we assume a mis - labeling in the options, as the question asks for moles of ammonium nitrate and the options are mis - named with 'O' instead of \(NH_4NO_3\))