Question

how many grams of rboh are present in 153 ml of a 4.88 m rboh solution? report your answer to one place after the decimal point.

Explanation:

Step1: Calculate the number of moles of RbOH

Use the formula \(n = C\times V\). Here, \(C = 4.88\space M\) (molarity) and \(V=153\space mL=0.153\space L\) (volume).
\(n = 4.88\times0.153\)
\(n = 0.74664\space mol\)

Step2: Calculate the mass of RbOH

The molar mass of \(RbOH\) is \(M=(85.47 + 16+ 1.01)\space g/mol=102.48\space g/mol\).
Use the formula \(m=n\times M\).
\(m = 0.74664\times102.48\)
\(m=76.5267672\space g\)

Answer:

\(76.5\space g\)