Question

how many grams of lif would be present in 575 ml of 0.750 m lif solution?
0.0338
19.9
1.12×10⁴
11.2
33.8

Explanation:

Step1: Convert volume to liters

$575\ \text{mL} = 575 \times 10^{-3}\ \text{L} = 0.575\ \text{L}$

Step2: Calculate moles of LiF

Moles = Molarity × Volume = $0.750\ \text{mol/L} × 0.575\ \text{L} = 0.43125\ \text{mol}$

Step3: Find molar mass of LiF

Molar mass = Li (6.94 g/mol) + F (19.00 g/mol) = $25.94\ \text{g/mol}$

Step4: Calculate mass of LiF

Mass = Moles × Molar mass = $0.43125\ \text{mol} × 25.94\ \text{g/mol} ≈ 11.2\ \text{g}$

Answer:

D. 11.2