Question

how many grams of calcium sulfate are needed to make 460.0 ml of a 0.100 m solution?

Explanation:

Step1: Calculate the number of moles of calcium sulfate

Use the formula \(n = C\times V\). Given \(C = 0.100\space M\) and \(V=460.0\space mL = 0.4600\space L\).
\(n=0.100\space mol/L\times0.4600\space L = 0.0460\space mol\)

Step2: Calculate the molar mass of calcium sulfate (\(CaSO_4\))

The molar mass of \(Ca = 40.08\space g/mol\), \(S = 32.07\space g/mol\), \(O = 16.00\space g/mol\).
\(M = 40.08+32.07 + 4\times16.00=136.15\space g/mol\)

Step3: Calculate the mass of calcium sulfate

Use the formula \(m=n\times M\).
\(m = 0.0460\space mol\times136.15\space g/mol=6.26\space g\)

Answer:

\(6.26\space g\)