Question

1. how many electrons would oxygen (o) need to have in its outer shell to be full? 1. what new compound did you create?

Explanation:

Step1: Determine the electron configuration of oxygen

Oxygen has an atomic number of 8. Its electron configuration is \(1s^{2}2s^{2}2p^{4}\). The outer shell (second shell) has \(2s^{2}2p^{4}\), so there are \(2 + 4=6\) electrons in the outer shell.

Step2: Recall the octet rule

The octet rule states that atoms tend to gain, lose, or share electrons to have 8 electrons in their outer shell (except for hydrogen and helium which follow the duet rule).

Answer:

Oxygen needs \(2\) more electrons to have a full outer shell (8 electrons in total in the outer shell).