how many atoms are present in 7.0 moles ca? 7.0 moles ca 1.2×10^{-23} atoms ca 6.02×10^{23} atoms ca 4.2×10^{24} atoms ca 8.6×10^{22} atoms ca

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Accepted Answer

# Explanation:
## Step1: Use Avogadro's number
Avogadro's number $N_A = 6.02\times10^{23}\text{ atoms/mol}$. The formula to find the number of atoms $N$ is $N=n\times N_A$, where $n$ is the number of moles.
## Step2: Substitute values
Given $n = 7.0\space mol$ of $Ca$. Then $N=7.0\space mol\times6.02\times 10^{23}\space\text{atoms/mol}$.
$$
\begin{align*}
N&=(7.0\times6.02)\times10^{23}\space\text{atoms}\
& = 42.14\times10^{23}\space\text{atoms}\
&=4.214\times 10^{24}\space\text{atoms}\approx4.2\times 10^{24}\space\text{atoms}
\end{align*}
$$

# Answer:
$4.2\times 10^{24}\space\text{atoms Ca}$ (the third option)

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Question

Explanation:

Step1: Use Avogadro's number

Step2: Substitute values

Answer: