Question

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6 of 10
review | constants | periodic table
part a
te
express your answer in condensed form in order of increasing orbital energy as a string without blank space between orbitals.
for example, he2s²2p² should be entered as he2s^22p^2.
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Explanation:

Step1: Determine the atomic number of Te

Tellurium (Te) has an atomic number of 52.

Step2: Find the noble gas core

The noble gas before Te is Kr (atomic number 36).

Step3: Write the remaining electrons

After [Kr], there are 52 - 36 = 16 electrons. The electron configuration for the remaining electrons is \(5s^{2}4d^{10}5p^{4}\)

Answer:

[Kr]5s^24d^105p^4