Question

a health instructor surveyed all her students, and tallied the results. the first survey question asked, \do you adhere to a vegetarian diet or omnivorous diet?\ the second question asked, \approximately how often do you exercise?\ what is the probability that a randomly selected student exercises daily and adheres to an omnivorous diet? simplify any fractions.

Explanation:

Step1: Find the number of students who exercise daily and adhere to an omnivorous diet

From the table, the number of students who exercise daily and adhere to an omnivorous diet is \(1\).

Step2: Find the total number of students

The total number of students is \(2 + 1+4 + 3=10\).

Step3: Calculate the probability

The probability \(P\) is given by the formula \(P=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}\). Here, the number of favorable outcomes is \(1\) (students who exercise daily and have an omnivorous diet) and the total number of outcomes is \(10\). So \(P = \frac{1}{10}\).

Answer:

\(\frac{1}{10}\)